Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №2173083
А
Аноним
10 ноября 2024 22:12 · публичный вопрос
А
Аноним

31+4•|4-x| = 47

Нейросеть10 ноября 2024 22:12

To solve the equation \( 31 + 4 \cdot |4 - x| = 47 \), follow these steps:

  1. Isolate the absolute value term: \[ 4 \cdot |4 - x| = 47 - 31 \] \[ 4 \cdot |4 - x| = 16 \]

  2. Divide both sides by 4: \[ |4 - x| = \frac{16}{4} \] \[ |4 - x| = 4 \]

  3. Set up the two cases for the absolute value: Case 1: \( 4 - x = 4 \)
    Case 2: \( 4 - x = -4 \)

  4. Solve each case:

    • For Case 1: \[ 4 - x = 4 \implies -x = 0 \implies x = 0 \]

    • For Case 2: \[ 4 - x = -4 \implies -x = -8 \implies x = 8 \]

  5. Final solutions: The solutions to the equation are \( x = 0 \) and \( x = 8 \).

31+4•|4-x| = 47
To solve the equation \( 31 + 4 \cdot |4 - x| = 47 \), follow these steps: 1. **Isolate the absolute value term**: \[ 4 \cdot |4 - x| = 47 - 31 \] \[ 4 \cdot |4 - x| = 16 \] 2. **Divide both sides by 4**: \[ |4 - x| = \frac{16}{4} \] \[ |4 - x| = 4 \] 3. **Set up the two cases for the absolute value**: Case 1: \( 4 - x = 4 \) Case 2: \( 4 - x = -4 \) 4. **Solve each case**: - For Case 1: \[ 4 - x = 4 \implies -x = 0 \implies x = 0 \] - For Case 2: \[ 4 - x = -4 \implies -x = -8 \implies x = 8 \] 5. **Final solutions**: The solutions to the equation are \( x = 0 \) and \( x = 8 \).