{y=3x {4x-y-3=0

It looks like you're working with two equations. The first equation is \( y = 3x \), and the second equation is \( 4x - y - 3 = 0 \).

Let's solve this system of equations. First, we can substitute the first equation into the second equation.

1. Substitute \( y \) from the first equation into the second:

\[ 4x - (3x) - 3 = 0 \]

2. Simplify the equation:

\[ 4x - 3x - 3 = 0 \]

This simplifies to:

\[ x - 3 = 0 \]

3. Solve for \( x \):

\[ x = 3 \]

4. Now, substitute \( x = 3 \) back into the first equation to find \( y \):

\[ y = 3(3) = 9 \]

So the solution to this system of equations is \( (x, y) = (3, 9) \).

If you have any further questions, feel free to ask!