To solve the expression \( 3458 + 7658 - (3218 - 2378) + 2168 \), let's break it down step by step:
Calculate \( 3218 - 2378 \): \[ 3218 - 2378 = 840 \]
Now substitute this back into the expression: \[ 3458 + 7658 - 840 + 2168 \]
Now let's add and subtract these numbers:
First, add \( 3458 + 7658 \): \[ 3458 + 7658 = 11116 \]
Next, subtract \( 840 \): \[ 11116 - 840 = 10276 \]
Finally, add \( 2168 \): \[ 10276 + 2168 = 12444 \]
Thus, the result of the arithmetic expression is \( 12444 \).
Next, let's convert the decimal number \( 1358 \) to base 6.
Divide \( 1358 \) by \( 6 \):
- \( 1358 \div 6 = 226\) remainder \( 2 \)
- So, the least significant digit (rightmost) in base 6 is \( 2 \).
Divide \( 226 \) by \( 6 \):
- \( 226 \div 6 = 37\) remainder \( 4 \)
- The next digit is \( 4 \).
Divide \( 37 \) by \( 6 \):
- \( 37 \div 6 = 6 \) remainder \( 1 \)
- The next digit is \( 1 \).
Divide \( 6 \) by \( 6 \):
- \( 6 \div 6 = 1 \) remainder \( 0 \)
- The next digit is \( 0 \).
Lastly, divide \( 1 \) by \( 6 \):
- \( 1 \div 6 = 0 \) remainder \( 1 \)
- The next digit is \( 1 \).
Now, we compile the remainders from last to first: So, \( 1358 \) in base \( 6 \) is written as \( 104242_6 \).
Final Summary:
- The result of the expression is \( 12444 \).
- The number \( 1358 \) in base \( 6 \) is \( 104242_6 \).