To simplify the expression \( \frac{5}{7}x + \frac{1}{3}x - 0.75 \cdot \frac{2}{3}x \), we will follow these steps:
First, let's convert \( 0.75 \) to a fraction. Since \( 0.75 = \frac{3}{4} \), we can rewrite the expression:
\[ \frac{5}{7}x + \frac{1}{3}x - \frac{3}{4} \cdot \frac{2}{3}x \]
Now, calculate \( \frac{3}{4} \cdot \frac{2}{3} \):
\[ \frac{3}{4} \cdot \frac{2}{3} = \frac{3 \cdot 2}{4 \cdot 3} = \frac{6}{12} = \frac{1}{2} \]
Thus, the expression becomes:
\[ \frac{5}{7}x + \frac{1}{3}x - \frac{1}{2}x \]
To combine these fractions, we need a common denominator. The least common multiple of \(7\), \(3\), and \(2\) is \(42\).
Convert each term to have a denominator of \(42\):
For \( \frac{5}{7}x \): \[ \frac{5}{7}x = \frac{5 \cdot 6}{7 \cdot 6}x = \frac{30}{42}x \]
For \( \frac{1}{3}x \): \[ \frac{1}{3}x = \frac{1 \cdot 14}{3 \cdot 14}x = \frac{14}{42}x \]
For \( \frac{1}{2}x \): \[ \frac{1}{2}x = \frac{1 \cdot 21}{2 \cdot 21}x = \frac{21}{42}x \]
Now, substitute these back into the expression:
\[ \frac{30}{42}x + \frac{14}{42}x - \frac{21}{42}x \]
Combine the fractions:
\[ \left( \frac{30 + 14 - 21}{42} \right)x = \frac{23}{42}x \]
Thus, the simplified expression is:
\[ \frac{23}{42}x \]
