(6y + 15) (2,4 - 0,8y) = 0

To solve the equation \((6y + 15)(2.4 - 0.8y) = 0\), we need to set each factor equal to zero.

1. First Factor: \(6y + 15 = 0\) \[ 6y = -15 \\ y = -\frac{15}{6} \\ y = -\frac{5}{2} \\ y = -2.5 \]

2. Second Factor: \(2.4 - 0.8y = 0\) \[ 0.8y = 2.4 \\ y = \frac{2.4}{0.8} \\ y = 3 \]

Thus, the solutions to the equation \((6y + 15)(2.4 - 0.8y) = 0\) are: \[ y = -2.5 \quad \text{and} \quad y = 3 \]