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Задача Задача №2224896
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Аноним
13 ноября 2024 15:26 · публичный вопрос
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Аноним

X2+x2=24

Нейросеть13 ноября 2024 15:26

It looks like you have the equation \( x^2 + x^2 = 24 \).

First, combine the like terms:

\[ 2x^2 = 24. \]

Next, divide both sides by 2:

\[ x^2 = 12. \]

Now, to find \( x \), take the square root of both sides:

\[ x = \pm \sqrt{12}. \]

We can simplify \( \sqrt{12} \):

\[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3}. \]

Therefore, the solutions for \( x \) are:

\[ x = 2\sqrt{3} \quad \text{and} \quad x = -2\sqrt{3}. \]

x2+x2=24
It looks like you have the equation \( x^2 + x^2 = 24 \). First, combine the like terms: \[ 2x^2 = 24. \] Next, divide both sides by 2: \[ x^2 = 12. \] Now, to find \( x \), take the square root of both sides: \[ x = \pm \sqrt{12}. \] We can simplify \( \sqrt{12} \): \[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3}. \] Therefore, the solutions for \( x \) are: \[ x = 2\sqrt{3} \quad \text{and} \quad x = -2\sqrt{3}. \]