Pb+CuO

The reaction between lead (Pb) and copper(II) oxide (CuO) can be classified as a reduction-oxidation (redox) reaction. In this reaction, lead reduces copper(II) oxide to copper while itself being oxidized to lead(II) oxide (PbO).

The balanced chemical equation for the reaction is:

\[ \text{Pb (s)} + \text{CuO (s)} \rightarrow \text{PbO (s)} + \text{Cu (s)} \]

Explanation:

• Pb is oxidized, going from an oxidation state of 0 to +2 in PbO.
• CuO is reduced, with Cu going from an oxidation state of +2 in CuO to 0 in elemental Cu.

This reaction is an example of a more reactive metal (lead) displacing a less reactive metal (copper) from its oxide, which illustrates the principles of the activity series of metals.

If you have any specific questions related to this reaction or if you need further details on topics like redox reactions, please feel free to ask!