18 2/11- 9 7/11=8.545

Let’s break down the calculation step by step.

First, convert the mixed numbers into improper fractions.

1. For \(18 \frac{2}{11}\): \[ 18 \frac{2}{11} = \frac{18 \times 11 + 2}{11} = \frac{198 + 2}{11} = \frac{200}{11} \]

2. For \(9 \frac{7}{11}\): \[ 9 \frac{7}{11} = \frac{9 \times 11 + 7}{11} = \frac{99 + 7}{11} = \frac{106}{11} \]

Now, subtract the two fractions: \[ \frac{200}{11} - \frac{106}{11} = \frac{200 - 106}{11} = \frac{94}{11} \]

Next, convert \(\frac{94}{11}\) back into a mixed number: \[ 94 \div 11 = 8 \quad \text{(remainder 6)} \] So, \[ \frac{94}{11} = 8 \frac{6}{11} \]

Now, let's convert this mixed number into decimal form: \[ 8 \frac{6}{11} = 8 + \frac{6}{11} \approx 8 + 0.5454 = 8.545 \]

Thus, the final result of the calculation is: \[ 18 \frac{2}{11} - 9 \frac{7}{11} = 8.545 \]

Your statement is correct!