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Аноним
16 ноября 2024 06:10 · публичный вопрос
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Аноним

Cos(x-7pi)-1

Нейросеть16 ноября 2024 06:10

To simplify the expression \( \cos(x - 7\pi) - 1 \), we can use the cosine function's periodicity and properties.

  1. The cosine function has a period of \( 2\pi \). This means that \( \cos(\theta) = \cos(\theta + 2k\pi) \) for any integer \( k \).

  2. We can rewrite \( 7\pi \) in terms of a multiple of \( 2\pi \): \[ 7\pi = 3 \cdot 2\pi + \pi \] Thus, we have: \[ \cos(x - 7\pi) = \cos(x - (6\pi + \pi)) = \cos(x - \pi) \]

  3. The cosine function has the property that \( \cos(x - \pi) = -\cos(x) \).

  4. Substitute back into the original expression: \[ \cos(x - 7\pi) - 1 = \cos(x - \pi) - 1 \] \[ = -\cos(x) - 1 \]

Therefore, the expression simplifies to: \[ -\cos(x) - 1 \] Or you could write it as: \[ -1 - \cos(x) \]

cos(x-7pi)-1
To simplify the expression \( \cos(x - 7\pi) - 1 \), we can use the cosine function's periodicity and properties. 1. The cosine function has a period of \( 2\pi \). This means that \( \cos(\theta) = \cos(\theta + 2k\pi) \) for any integer \( k \). 2. We can rewrite \( 7\pi \) in terms of a multiple of \( 2\pi \): \[ 7\pi = 3 \cdot 2\pi + \pi \] Thus, we have: \[ \cos(x - 7\pi) = \cos(x - (6\pi + \pi)) = \cos(x - \pi) \] 3. The cosine function has the property that \( \cos(x - \pi) = -\cos(x) \). 4. Substitute back into the original expression: \[ \cos(x - 7\pi) - 1 = \cos(x - \pi) - 1 \] \[ = -\cos(x) - 1 \] Therefore, the expression simplifies to: \[ -\cos(x) - 1 \] Or you could write it as: \[ -1 - \cos(x) \]