3x2+bx+3=0

To solve the quadratic equation \( 3x^2 + bx + 3 = 0 \) for \( x \), we need to know the value of \( b \). The general form of a quadratic equation is \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are coefficients.

Assuming \( a = 3 \), \( b = b \), and \( c = 3 \), we can use the quadratic formula:

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

Substituting in the values we have:

\[ x = \frac{-b \pm \sqrt{b^2 - 4(3)(3)}}{2(3)} \] \[ x = \frac{-b \pm \sqrt{b^2 - 36}}{6} \]

This gives us the solutions for \( x \) in terms of \( b \). If you have a specific value for \( b \), please provide it, and we can compute the values of \( x \).