To multiply the mixed numbers \(2 \frac{3}{4}\) and \(1 \frac{2}{8}\), first convert them into improper fractions.
Convert \(2 \frac{3}{4}\) to an improper fraction: \[ 2 \frac{3}{4} = \frac{2 \times 4 + 3}{4} = \frac{8 + 3}{4} = \frac{11}{4} \]
Convert \(1 \frac{2}{8}\) to an improper fraction: \[ 1 \frac{2}{8} = \frac{1 \times 8 + 2}{8} = \frac{8 + 2}{8} = \frac{10}{8} = \frac{5}{4} \quad \text{(simplifying, since 10 and 8 have a GCD of 2)} \]
Now, multiply the improper fractions: \[ \frac{11}{4} \times \frac{5}{4} = \frac{11 \times 5}{4 \times 4} = \frac{55}{16} \]
Now, if you want to express \(\frac{55}{16}\) as a mixed number: \[ \frac{55}{16} = 3 \frac{7}{16} \] (because \(55 \div 16 = 3\) with a remainder of \(7\))
So, the final answer is: \[ 2 \frac{3}{4} \times 1 \frac{2}{8} = \frac{55}{16} \text{ or } 3 \frac{7}{16} \]