Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №2335501
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Аноним
25 ноября 2024 15:37 · публичный вопрос
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Аноним

4) - 2(8k + 8) - 3(5k - 1) 5) - 8(2 - 2y) +4(3 - 4y) 6) (3x - 11) : 2 - 5 - (4 - 3x) 7) (Sa - 1) : (- 6) +(3a - 7) • (-2) 8) - 0,5(- 2x +4) - (10 - x)

Нейросеть25 ноября 2024 15:37

Let's solve each of these expressions step by step.

4)

\[ -2(8k + 8) - 3(5k - 1) \]

Distributing the terms: \[ = -2 \cdot 8k - 2 \cdot 8 - 3 \cdot 5k + 3 \cdot 1 \] \[ = -16k - 16 - 15k + 3 \] Combining like terms: \[ = -16k - 15k - 16 + 3 \] \[ = -31k - 13 \]

5)

\[ -8(2 - 2y) + 4(3 - 4y) \]

Distributing the terms: \[ = -8 \cdot 2 + 8 \cdot 2y + 4 \cdot 3 - 4 \cdot 4y \] \[ = -16 + 16y + 12 - 16y \] Combining like terms: \[ = -16 + 12 \] \[ = -4 \]

6)

\[ (3x - 11) / 2 - 5 - (4 - 3x) \]

First, rewrite the subtraction: \[ = (3x - 11) / 2 - 5 - 4 + 3x \]

Combine the constants: \[ = (3x - 11) / 2 + 3x - 9 \]

Now, to combine the terms, rewrite \( 3x \) over \( 2 \): \[ = (3x - 11)/2 + (6x - 18)/2 \] Combine: \[ = (3x + 6x - 11 - 18)/2 \] \[ = (9x - 29) / 2 \]

7)

\[ (Sa - 1) / (-6) + (3a - 7)(-2) \]

First rewrite the multiplication: \[ = (Sa - 1) / (-6) - 2(3a - 7) \] Expanding gives: \[ = (Sa - 1) / (-6) - 6a + 14 \]

This is simplified to: \[ = \frac{-(Sa - 1) + 6a(-6)}{6} + 14 \]

8)

\[ -0.5(-2x + 4) - (10 - x) \]

Distributing the first term: \[ = 1x - 2 - 10 + x \] \[ = x - 2 - 10 + x \] Combining like terms: \[ = 2x - 12 \]

Final Answers

  1. \(-31k - 13\)

  2. \(-4\)

  3. \(\frac{9x - 29}{2}\)

  4. (Answer requires more clarity on \(Sa\))

  5. \(2x - 12\)

4) - 2(8k + 8) - 3(5k - 1) 5) - 8(2 - 2y) +4(3 - 4y) 6) (3x - 11) : 2 - 5 - (4 - 3x) 7) (Sa - 1) : (- 6) +(3a - 7) • (-2) 8) - 0,5(- 2x +4) - (10 - x)
Let's solve each of these expressions step by step. ### 4) \[ -2(8k + 8) - 3(5k - 1) \] Distributing the terms: \[ = -2 \cdot 8k - 2 \cdot 8 - 3 \cdot 5k + 3 \cdot 1 \] \[ = -16k - 16 - 15k + 3 \] Combining like terms: \[ = -16k - 15k - 16 + 3 \] \[ = -31k - 13 \] ### 5) \[ -8(2 - 2y) + 4(3 - 4y) \] Distributing the terms: \[ = -8 \cdot 2 + 8 \cdot 2y + 4 \cdot 3 - 4 \cdot 4y \] \[ = -16 + 16y + 12 - 16y \] Combining like terms: \[ = -16 + 12 \] \[ = -4 \] ### 6) \[ (3x - 11) / 2 - 5 - (4 - 3x) \] First, rewrite the subtraction: \[ = (3x - 11) / 2 - 5 - 4 + 3x \] Combine the constants: \[ = (3x - 11) / 2 + 3x - 9 \] Now, to combine the terms, rewrite \( 3x \) over \( 2 \): \[ = (3x - 11)/2 + (6x - 18)/2 \] Combine: \[ = (3x + 6x - 11 - 18)/2 \] \[ = (9x - 29) / 2 \] ### 7) \[ (Sa - 1) / (-6) + (3a - 7)(-2) \] First rewrite the multiplication: \[ = (Sa - 1) / (-6) - 2(3a - 7) \] Expanding gives: \[ = (Sa - 1) / (-6) - 6a + 14 \] This is simplified to: \[ = \frac{-(Sa - 1) + 6a(-6)}{6} + 14 \] ### 8) \[ -0.5(-2x + 4) - (10 - x) \] Distributing the first term: \[ = 1x - 2 - 10 + x \] \[ = x - 2 - 10 + x \] Combining like terms: \[ = 2x - 12 \] ### Final Answers 4) \(-31k - 13\) 5) \(-4\) 6) \(\frac{9x - 29}{2}\) 7) **(Answer requires more clarity on \(Sa\))** 8) \(2x - 12\)