To simplify the given expression \( \frac{2}{7} \times 10 \, \frac{4}{5} : \frac{1}{7} : 30 : 1 \, \frac{11}{25} \times 8 : \frac{1}{6} \), let's break it down step by step.
First, convert the mixed numbers into improper fractions:
- \( 10 \, \frac{4}{5} = 10 + \frac{4}{5} = \frac{50}{5} + \frac{4}{5} = \frac{54}{5} \)
- \( 1 \, \frac{11}{25} = 1 + \frac{11}{25} = \frac{25}{25} + \frac{11}{25} = \frac{36}{25} \)
Now we can rewrite the full expression using improper fractions:
\[ \frac{2}{7} \times \frac{54}{5} : \frac{1}{7} : 30 : \frac{36}{25} \times 8 : \frac{1}{6} \]
Next, let's calculate each part individually.
Step 1: Calculate \( \frac{2}{7} \times \frac{54}{5} \)
\[ \frac{2 \times 54}{7 \times 5} = \frac{108}{35} \]
Step 2: The rest of the parts
Now let's deal with the division of parts marked by the ":"
The expression can be converted into multiplication by flipping the denominators:
\[ \frac{108}{35} \div \frac{1}{7} \div 30 \div \frac{36}{25} \div \frac{1}{6} \]
This is equivalent to:
\[ \frac{108}{35} \times 7 \times \frac{1}{30} \times \frac{25}{36} \times 6 \]
Step 3: Combine all the multiplications together
Now perform the multiplications step by step:
- \( \frac{108}{35} \times 7 = \frac{756}{35} \)
- \( \frac{756}{35} \div 30 = \frac{756}{35 \times 30} = \frac{756}{1050} \)
- \( \frac{756}{1050} \times \frac{25}{36} = \frac{756 \times 25}{1050 \times 36} \)
- \( \frac{756 \times 25}{1050 \times 36} \times 6 = \frac{756 \times 25 \times 6}{1050 \times 36} \)
Final Step: Calculate the final fraction
- Calculate the numerator: \( 756 \times 25 \times 6 \)
- Calculate the denominator: \( 1050 \times 36 \)
Now we can compute those products for the final answer:
- Numerator: \( 756 \times 25 = 18900 \) and \( 18900 \times 6 = 113400 \)
- Denominator: \( 1050 \times 36 = 37800 \)
Now we have:
\[ \frac{113400}{37800} \]
This fraction can be simplified by finding the GCD of 113400 and 37800, which gives us:
\[ \frac{113400 \div 37800}{37800 \div 37800} = \frac{3}{1} = 3 \]
Therefore, the simplified expression is:
\[ \boxed{3} \]