M(Na3Po4)=150г n-?

To find the number of moles (n) of sodium phosphate (\(Na_3PO_4\)), you can use the formula:

\[ n = \frac{m}{M} \]

where:

• \(n\) = number of moles,
• \(m\) = mass of the substance (in grams),
• \(M\) = molar mass of the substance (in grams per mole).

The molar mass of sodium phosphate (\(Na_3PO_4\)) can be calculated as follows:

• Sodium (Na): 23 g/mol
• Phosphorus (P): 31 g/mol
• Oxygen (O): 16 g/mol

Calculating the molar mass:

\[ M = 3 \times 23 \, \text{g/mol (for Na)} + 31 \, \text{g/mol (for P)} + 4 \times 16 \, \text{g/mol (for O)} \] \[ M = 69 + 31 + 64 = 164 \, \text{g/mol} \]

Now you can calculate \(n\) using your mass (\(m = 150 \, \text{g}\)):

\[ n = \frac{150 \, \text{g}}{164 \, \text{g/mol}} \approx 0.915 \, \text{mol} \]

Therefore, the number of moles (\(n\)) of sodium phosphate in 150 g is approximately \(0.915\) moles.