X2+2y=0

The equation you've provided is \( x^2 + 2y = 0 \).

To solve for \( y \), you can rearrange the equation:

\[ 2y = -x^2 \] \[ y = -\frac{x^2}{2} \]

This represents a downward-opening parabola in the \( xy \)-plane with its vertex at the origin \((0, 0)\).

If you have a specific question about this equation, such as finding intersections, graphing, or solving for particular values of \(x\) and \(y\), please let me know!