It looks like you're trying to balance a chemical reaction involving iron (III) oxide (Fe₂O₃) reacting with carbon monoxide (CO) to produce iron (Fe) and carbon dioxide (CO₂). However, the initial formula contains a typographical error (Fez03 should be Fe₂O₃).
The balanced chemical equation is:
\[ \text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2 \]
Here's how to balance it step by step:
Identify all compounds and elements involved:
- Reactants: Iron(III) oxide (Fe₂O₃) and carbon monoxide (CO).
- Products: Iron (Fe) and carbon dioxide (CO₂).
Count the number of atoms for each element in the reactants and products:
- Reactants:
- Fe: 2 (from Fe₂O₃)
- O: 3 (from Fe₂O₃)
- C: 3 (from 3 CO)
- Products:
- Fe: 2 (from 2 Fe)
- C: 3 (from 3 CO₂)
- O: 6 (from 3 CO₂)
- Reactants:
Adjust coefficients:
- We have 2 iron atoms on both sides, so iron is balanced.
- There are 3 carbon atoms on both sides (3 CO in reactants and 3 CO₂ in products).
- Oxygen is initially unbalanced: we have 3 oxygen in the reactants and 6 in the products.
Final balanced equation:
- The final balanced equation is as shown above: \[ \text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2 \]
This equation is now balanced with respect to all elements involved.