22 + у? - 2х+6y = 0

To solve the equation \( 22 + y - 2x + 6y = 0 \), we can first simplify it.

Combine the \(y\) terms:

\[ 22 + (1y + 6y) - 2x = 0 \]

This simplifies to:

\[ 22 + 7y - 2x = 0 \]

Now, we can isolate either \(x\) or \(y\). Let's isolate \(y\):

\[ 7y = 2x - 22 \]

Dividing by 7 gives us:

\[ y = \frac{2x - 22}{7} \]

You can also rearrange the equation to solve for \(x\):

\[ -2x = -7y - 22 \]

Then multiply by -1:

\[ 2x = 7y + 22 \]

Finally, divide by 2:

\[ x = \frac{7y + 22}{2} \]

So, we have two expressions:

1. \(y = \frac{2x - 22}{7}\)
2. \(x = \frac{7y + 22}{2}\)

These equations represent the relationship between \(x\) and \(y\). You can choose either to express one variable in terms of the other depending on your requirements.