y^2-8y+16=0

To solve the quadratic equation \( y^2 - 8y + 16 = 0 \), we can factor the expression.

Notice that the equation can be rewritten as:

\[ (y - 4)(y - 4) = 0 \]

or

\[ (y - 4)^2 = 0 \]

Setting the factored form equal to zero, we get:

\[ y - 4 = 0 \]

Solving for \( y \) gives:

\[ y = 4 \]

Thus, the solution to the equation \( y^2 - 8y + 16 = 0 \) is \( y = 4 \). This is a repeated root, meaning it has a multiplicity of 2.