LiF + Mg(NO,), → LiNO, + MgF,
To balance the chemical equation for the reaction between lithium fluoride (LiF) and magnesium nitrate (Mg(NO₃)₂), we first write down the unbalanced reaction:
\[ \text{LiF} + \text{Mg(NO}_3)_2 \rightarrow \text{LiNO}_3 + \text{MgF}_2 \]
Next, we can count the number of each type of atom on both sides of the equation:
Left side:
- Lithium (Li): 1 (from LiF)
- Fluorine (F): 1 (from LiF)
- Magnesium (Mg): 1 (from Mg(NO₃)₂)
- Nitrogen (N): 2 (from Mg(NO₃)₂)
- Oxygen (O): 6 (from Mg(NO₃)₂)
Right side:
- Lithium (Li): 1 (from LiNO₃)
- Fluorine (F): 2 (from MgF₂)
- Magnesium (Mg): 1 (from MgF₂)
- Nitrogen (N): 1 (from LiNO₃)
- Oxygen (O): 3 (from LiNO₃)
Now, to balance the equation, we need to ensure that the number of each type of atom is the same on both sides.
Each molecule of \( \text{Mg(NO}_3)_2 \) yields 2 moles of \( \text{NO}_3^- \) ions. Thus, we will have to adjust the coefficients so that we balance the nitrogens and oxygens.
The balanced equation will look like this:
\[ 2 \text{LiF} + \text{Mg(NO}_3)_2 \rightarrow 2 \text{LiNO}_3 + \text{MgF}_2 \]
Now, recheck the counts:
Left side:
- Lithium (Li): 2
- Fluorine (F): 2
- Magnesium (Mg): 1
- Nitrogen (N): 2
- Oxygen (O): 6
Right side:
- Lithium (Li): 2
- Fluorine (F): 2
- Magnesium (Mg): 1
- Nitrogen (N): 2
- Oxygen (O): 6
Now, both sides have the same number of each type of atom. Thus, the balanced equation is:
\[ 2 \text{LiF} + \text{Mg(NO}_3)_2 \rightarrow 2 \text{LiNO}_3 + \text{MgF}_2 \]
