2x*x-32/25=0

To solve the equation \(2x^2 - \frac{32}{25} = 0\), we can start by isolating \(x^2\).

1. Rewrite the equation: \[ 2x^2 = \frac{32}{25} \]

2. Divide both sides by 2: \[ x^2 = \frac{32}{25 \cdot 2} = \frac{32}{50} = \frac{16}{25} \]

3. Now take the square root of both sides: \[ x = \pm \sqrt{\frac{16}{25}} = \pm \frac{4}{5} \]

So, the solutions for the equation \(2x^2 - \frac{32}{25} = 0\) are: \[ x = \frac{4}{5} \quad \text{and} \quad x = -\frac{4}{5} \]