(8-х)(3х-3)(4х+20)=0

To solve the equation \((8 - x)(3x - 3)(4x + 20) = 0\), we can set each factor equal to zero and solve for \(x\).

1. First factor: \[ 8 - x = 0 \\ x = 8 \]

2. Second factor: \[ 3x - 3 = 0 \\ 3x = 3 \\ x = 1 \]

3. Third factor: \[ 4x + 20 = 0 \\ 4x = -20 \\ x = -5 \]

Now we have the solutions: \[ x = 8, \quad x = 1, \quad x = -5 \]

Thus, the complete set of solutions to the equation \((8 - x)(3x - 3)(4x + 20) = 0\) is: \[ x = 8, \quad x = 1, \quad x = -5 \]