t - 36t + 77 =

It looks like you have a quadratic equation that needs to be simplified or solved. However, there seems to be a slight error in the equation you've provided. If you meant to write it as:

\( t^2 - 36t + 77 = 0 \)

then we can proceed to solve it. To solve this quadratic equation, we can use the quadratic formula:

\[ t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

where \( a = 1 \), \( b = -36 \), and \( c = 77 \).

1. Calculate the discriminant:

\[ b^2 - 4ac = (-36)^2 - 4 \cdot 1 \cdot 77 = 1296 - 308 = 988 \]

2. Now apply the quadratic formula:

\[ t = \frac{-(-36) \pm \sqrt{988}}{2 \cdot 1} = \frac{36 \pm \sqrt{988}}{2} \]

3. Simplify \( \sqrt{988} \):

First, factor \( 988 \):

\[ 988 = 4 \cdot 247 = 4 \cdot (247) \]

So, \( \sqrt{988} = \sqrt{4 \cdot 247} = 2\sqrt{247} \).

4. Substitute back:

\[ t = \frac{36 \pm 2\sqrt{247}}{2} \]

This simplifies to:

\[ t = 18 \pm \sqrt{247} \]

So the solutions for the equation \( t^2 - 36t + 77 = 0 \) are:

\[ t = 18 + \sqrt{247} \quad \text{and} \quad t = 18 - \sqrt{247} \]

If you meant something different with your equation, please clarify!