To solve the equation \( 2a \cdot 6x^3 = x \), we can first simplify the left side:
\[ 12a x^3 = x \]
Next, we can rearrange the equation by getting all terms to one side:
\[ 12a x^3 - x = 0 \]
Factoring out \( x \):
\[ x(12a x^2 - 1) = 0 \]
This gives us two cases to consider:
- \( x = 0 \)
- \( 12a x^2 - 1 = 0 \)
For the second case, we can solve for \( x \):
\[ 12a x^2 = 1 \] \[ x^2 = \frac{1}{12a} \] \[ x = \pm \sqrt{\frac{1}{12a}} \]
Thus, the solutions to the equation \( 2a \cdot 6x^3 = x \) are:
\[ x = 0, \quad x = \sqrt{\frac{1}{12a}}, \quad x = -\sqrt{\frac{1}{12a}} \]
These are the values of \( x \) that satisfy the original equation.
