y=xx-4x+4

It looks like you have a quadratic equation in the form of \( y = x^2 - 4x + 4 \).

To analyze this quadratic, we can do the following:

1. Rewrite in Vertex Form: The given quadratic \( y = x^2 - 4x + 4 \) can be rewritten by completing the square.

   \[ y = x^2 - 4x + 4 \] This simplifies directly: \[ y = (x - 2)^2 \]

2. Identify Key Features:

   • Vertex: The vertex form shows that the vertex of the parabola is at the point \( (2, 0) \).
   • Axis of Symmetry: The axis of symmetry is the line \( x = 2 \).
   • Direction: Since the coefficient of \( x^2 \) is positive, the parabola opens upwards.

3. Intercepts:

   • Y-Intercept: Set \( x = 0 \): \[ y = 0^2 - 4(0) + 4 = 4 \] So the y-intercept is at \( (0, 4) \).
   • X-Intercepts: Set \( y = 0 \): \[ (x - 2)^2 = 0 \implies x - 2 = 0 \implies x = 2 \] So the x-intercept is also at \( (2, 0) \).

4. Graphing: You would plot the vertex at \( (2, 0) \), draw the axis of symmetry at \( x = 2 \), and plot the y-intercept at \( (0, 4) \). The parabola will open upwards.

If you have specific questions about this equation or need help with related topics, feel free to ask!