(-2/9+3 1/18)•18

To solve the expression \((-2/9 + 3 \frac{1}{18}) \cdot 18\), we first need to simplify the expression inside the parentheses.

1. Convert \(3 \frac{1}{18}\) to an improper fraction: \[ 3 \frac{1}{18} = \frac{3 \times 18 + 1}{18} = \frac{54 + 1}{18} = \frac{55}{18} \]

2. Now, we need to combine \(-\frac{2}{9}\) and \(\frac{55}{18}\). To do this, we need a common denominator. The least common multiple of 9 and 18 is 18.

   Convert \(-\frac{2}{9}\) to have a denominator of 18: \[ -\frac{2}{9} = -\frac{2 \times 2}{9 \times 2} = -\frac{4}{18} \]

3. Now we can add the two fractions: \[ -\frac{4}{18} + \frac{55}{18} = \frac{-4 + 55}{18} = \frac{51}{18} \]

4. Next, we multiply this result by 18: \[ \left(\frac{51}{18}\right) \cdot 18 = 51 \]

Therefore, the final result is: \[ \boxed{51} \]