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Задача Задача №2476989
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Аноним
12 декабря 2024 03:04 · публичный вопрос
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Аноним

21,9*10кг:3*10-6м3

Нейросеть12 декабря 2024 03:04

To simplify the expression \( \frac{21.9 \times 10^k \text{ kg}}{3 \times 10^{-6} \text{ m}^3} \), follow these steps:

  1. Divide the coefficients (21.9 and 3).
  2. Subtract the exponents of 10 (since you are dividing).

Let's do the calculation:

  1. Divide the coefficients: \[ \frac{21.9}{3} = 7.3 \]

  2. Now, for the powers of ten: \[ 10^k / 10^{-6} = 10^{k - (-6)} = 10^{k + 6} \]

Putting it all together: \[ \frac{21.9 \times 10^k \text{ kg}}{3 \times 10^{-6} \text{ m}^3} = 7.3 \times 10^{k + 6} \frac{\text{kg}}{\text{m}^3} \]

So the final result is: \[ 7.3 \times 10^{k + 6} \text{ kg/m}^3 \]

21,9*10кг:3*10-6м3
To simplify the expression \( \frac{21.9 \times 10^k \text{ kg}}{3 \times 10^{-6} \text{ m}^3} \), follow these steps: 1. Divide the coefficients (21.9 and 3). 2. Subtract the exponents of 10 (since you are dividing). Let's do the calculation: 1. Divide the coefficients: \[ \frac{21.9}{3} = 7.3 \] 2. Now, for the powers of ten: \[ 10^k / 10^{-6} = 10^{k - (-6)} = 10^{k + 6} \] Putting it all together: \[ \frac{21.9 \times 10^k \text{ kg}}{3 \times 10^{-6} \text{ m}^3} = 7.3 \times 10^{k + 6} \frac{\text{kg}}{\text{m}^3} \] So the final result is: \[ 7.3 \times 10^{k + 6} \text{ kg/m}^3 \]