(2x - 1) 2x - 5x < 4х2- х

To solve the inequality \((2x - 1)2x - 5x < 4x^2 - x\), we'll start by expanding and rearranging the terms.

1. Expand the left-hand side: \[ (2x - 1)2x = 4x^2 - 2x \]

   Now plug that back into the inequality: \[ 4x^2 - 2x - 5x < 4x^2 - x \]

2. Combine like terms on the left-hand side: \[ 4x^2 - 7x < 4x^2 - x \]

3. Subtract \(4x^2\) from both sides: \[ -7x < -x \]

4. Add \(x\) to both sides to isolate terms with \(x\): \[ -6x < 0 \]

5. Divide both sides by -6 (remember, dividing or multiplying both sides of an inequality by a negative number flips the inequality sign): \[ x > 0 \]

Thus, the solution to the inequality is: \[ x > 0 \]

If you have any more questions or need further assistance with inequalities, feel free to ask!