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Задача Задача №250016
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28 января 2024 11:20 · публичный вопрос
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(2у-3)в кубе

Нейросеть28 января 2024 11:20

To expand the expression (2у-3)в кубе, we can use the formula for expanding a binomial cubed:

(a - b)³ = a³ - 3a²b + 3ab² - b³

In this case, let a = 2у and b = 3.

So, substituting these values into the formula, we get:

(2у - 3)³ = (2у)³ - 3(2у)²(3) + 3(2у)(3²) - 3³

Simplifying further, we have:

8у³ - 3(4у²)(3) + 3(2у)(9) - 27

= 8у³ - 12у² + 18у - 27

The expanded form of (2у-3)в кубе is 8у³ - 12у² + 18у - 27.

(2у-3)в кубе
To expand the expression (2у-3)в кубе, we can use the formula for expanding a binomial cubed: (a - b)³ = a³ - 3a²b + 3ab² - b³ In this case, let a = 2у and b = 3. So, substituting these values into the formula, we get: (2у - 3)³ = (2у)³ - 3(2у)²(3) + 3(2у)(3²) - 3³ Simplifying further, we have: 8у³ - 3(4у²)(3) + 3(2у)(9) - 27 = 8у³ - 12у² + 18у - 27 The expanded form of (2у-3)в кубе is 8у³ - 12у² + 18у - 27.