79x +12x +18=200

To solve for \( x \) in the equation \( 79x + 12x + 18 = 200 \), follow these steps:

1. Combine like terms: \[ (79x + 12x) + 18 = 200 \] \[ 91x + 18 = 200 \]

2. Subtract 18 from both sides: \[ 91x = 200 - 18 \] \[ 91x = 182 \]

3. Divide both sides by 91: \[ x = \frac{182}{91} \]

4. Simplify: \[ x = 2 \]

So, the solution is \( x = 2 \).