Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №2510080
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Аноним
16 декабря 2024 15:44 · публичный вопрос
А
Аноним

(6,75-4,5•1 2/3)•(-1 1/3)3

Нейросеть16 декабря 2024 15:44

To solve the expression \( (6.75 - 4.5 \cdot 1 \frac{2}{3}) \cdot (-1 \frac{1}{3})^3 \), we can follow these steps:

  1. Convert mixed and fractional numbers to improper fractions:

    • \( 1 \frac{2}{3} = \frac{5}{3} \)
    • \( -1 \frac{1}{3} = -\frac{4}{3} \)
  2. Calculate \( 4.5 \cdot 1 \frac{2}{3} \): \[ 4.5 \cdot \frac{5}{3} = \frac{4.5 \cdot 5}{3} = \frac{22.5}{3} = 7.5 \]

  3. Substitute back into the expression: \[ (6.75 - 7.5) \cdot (-\frac{4}{3})^3 \]

  4. Calculate \( 6.75 - 7.5 \): \[ 6.75 - 7.5 = -0.75 \]

  5. Calculate \( (-\frac{4}{3})^3 \): \[ (-\frac{4}{3})^3 = -\frac{4^3}{3^3} = -\frac{64}{27} \]

  6. Combine the results: \[ -0.75 \cdot -\frac{64}{27} \] Convert \(-0.75\) to a fraction: \[ -0.75 = -\frac{3}{4} \]

  7. Multiply the fractions: \[ -\frac{3}{4} \cdot -\frac{64}{27} = \frac{3 \cdot 64}{4 \cdot 27} = \frac{192}{108} = \frac{16}{9} \quad (\text{after simplification}) \]

So, the final answer is: \[ \frac{16}{9} \]

(6,75-4,5•1 2/3)•(-1 1/3)3
To solve the expression \( (6.75 - 4.5 \cdot 1 \frac{2}{3}) \cdot (-1 \frac{1}{3})^3 \), we can follow these steps: 1. **Convert mixed and fractional numbers to improper fractions**: - \( 1 \frac{2}{3} = \frac{5}{3} \) - \( -1 \frac{1}{3} = -\frac{4}{3} \) 2. **Calculate \( 4.5 \cdot 1 \frac{2}{3} \)**: \[ 4.5 \cdot \frac{5}{3} = \frac{4.5 \cdot 5}{3} = \frac{22.5}{3} = 7.5 \] 3. **Substitute back into the expression**: \[ (6.75 - 7.5) \cdot (-\frac{4}{3})^3 \] 4. **Calculate \( 6.75 - 7.5 \)**: \[ 6.75 - 7.5 = -0.75 \] 5. **Calculate \( (-\frac{4}{3})^3 \)**: \[ (-\frac{4}{3})^3 = -\frac{4^3}{3^3} = -\frac{64}{27} \] 6. **Combine the results**: \[ -0.75 \cdot -\frac{64}{27} \] Convert \(-0.75\) to a fraction: \[ -0.75 = -\frac{3}{4} \] 7. **Multiply the fractions**: \[ -\frac{3}{4} \cdot -\frac{64}{27} = \frac{3 \cdot 64}{4 \cdot 27} = \frac{192}{108} = \frac{16}{9} \quad (\text{after simplification}) \] So, the final answer is: \[ \frac{16}{9} \]