al2(so4)3+hno3=
To balance the reaction between aluminum sulfate \((\text{Al}_2(\text{SO}_4)_3)\) and nitric acid \((\text{HNO}_3)\), we consider the potential products. The aluminum sulfate can react with nitric acid to produce aluminum nitrate, sulfuric acid, and water.
The unbalanced reaction can be formulated as follows:
\[ \text{Al}_2(\text{SO}_4)_3 + \text{HNO}_3 \rightarrow \text{Al(NO}_3\text{)}_3 + \text{H}_2\text{SO}_4 \]
Balancing the equation requires ensuring that the number of each type of atom is the same on both sides:
- Aluminum (Al): There are 2 Al in aluminum sulfate, so we need 2 aluminum nitrate.
- Nitrate (NO₃): Each aluminum nitrate contains 3 NO₃, so for 2 aluminum nitrates, we need \(2 \times 3 = 6 \) nitrate ions.
- Hydrogen (H): The 6 hydrogen atoms will come from 6 nitric acid.
- Sulfur (S) and Oxygen (O): There are 3 sulfate ions in aluminum sulfate, providing 3 sulfur atoms that will correspond to 3 sulfuric acid molecules.
Overall, the balanced equation is:
\[ \text{Al}_2(\text{SO}_4)_3 + 6 \text{HNO}_3 \rightarrow 2 \text{Al(NO}_3\text{)}_3 + 3 \text{H}_2\text{SO}_4 \]
This balanced equation represents the complete reaction between aluminum sulfate and nitric acid, resulting in aluminum nitrate and sulfuric acid.
