(4/9-3 1/15)•9

To solve the expression \((\frac{4}{9} - 3 \frac{1}{15}) \cdot 9\), we can follow these steps:

1. Convert the mixed number \(3 \frac{1}{15}\) to an improper fraction: \[ 3 \frac{1}{15} = 3 + \frac{1}{15} = \frac{3 \cdot 15}{15} + \frac{1}{15} = \frac{45 + 1}{15} = \frac{46}{15} \]

2. Now, subtract \(\frac{4}{9}\) from \(\frac{46}{15}\). To do this, we need a common denominator. The least common multiple of 9 and 15 is 45.

3. Convert \(\frac{4}{9}\) and \(\frac{46}{15}\) to have a denominator of 45: \[ \frac{4}{9} = \frac{4 \cdot 5}{9 \cdot 5} = \frac{20}{45} \] \[ \frac{46}{15} = \frac{46 \cdot 3}{15 \cdot 3} = \frac{138}{45} \]

4. Now subtract the former from the latter: \[ \frac{20}{45} - \frac{138}{45} = \frac{20 - 138}{45} = \frac{-118}{45} \]

5. Now multiply the result by 9: \[ \left(\frac{-118}{45}\right) \cdot 9 = \frac{-118 \cdot 9}{45} = \frac{-1062}{45} \]

6. Simplify if possible. The GCD of 1062 and 45 is 3. Dividing the numerator and denominator by 3: \[ \frac{-1062 \div 3}{45 \div 3} = \frac{-354}{15} \] Which simplifies further: \[ \frac{-354 \div 3}{15 \div 3} = \frac{-118}{5} \]

Thus, the final answer is: \[ \frac{-118}{5} \] or \(-23.6\) in decimal form.