(3x-2)(x+4)-3(x+5)(x-1)=0

Решим данное уравнение:

(3x-2)(x+4)-3(x+5)(x-1)=0

Распределяем множители:

(3x-2)x + (3x-2)4 -3(x+5)(x-1) = 0

3x^2 - 2x + 12x - 8 - 3(x^2 - x + 5x - 5) = 0

3x^2 - 2x + 12x - 8 - 3x^2 + 3x - 15 = 0

3x^2 and -3x^2 cancel each other out, as well as -2x and 3x:

10x - 23 = 0

Now we can solve for x:

10x = 23

x = 23/10

Ответ: x = 23/10