To simplify the expression \((a + 3) + (a - 3)(a + 3) + ba\), we will first expand the second term \((a - 3)(a + 3)\) using the difference of squares formula:
\[ (a - 3)(a + 3) = a^2 - 9 \]
Now substituting back into the expression:
\[ (a + 3) + (a^2 - 9) + ba \]
Next, combine like terms:
- The linear terms: \(a + 3 - 9 = a - 6\)
- The quadratic term: \(a^2\)
- The \(ba\) term stays as is.
So the expression simplifies to:
\[ a^2 + ba + (a - 6) \]
Thus, the final simplified expression is:
\[ a^2 + ba + a - 6 \]
Or simply:
\[ a^2 + (b + 1)a - 6 \]