40*(-0,1)²+2*(-0,1)³+5,1=

To solve the expression \( 40 \times (-0.1)^2 + 2 \times (-0.1)^3 + 5.1 \), let's break it down step by step:

1. Calculate \( (-0.1)^2 \): \[ (-0.1)^2 = 0.01 \]

2. Calculate \( 40 \times (-0.1)^2 \): \[ 40 \times 0.01 = 0.4 \]

3. Calculate \( (-0.1)^3 \): \[ (-0.1)^3 = -0.001 \]

4. Calculate \( 2 \times (-0.1)^3 \): \[ 2 \times -0.001 = -0.002 \]

5. Now, sum all the parts together: \[ 0.4 + (-0.002) + 5.1 \]

6. Combine the numbers: \[ 0.4 - 0.002 = 0.398 \] \[ 0.398 + 5.1 = 5.498 \]

The final result is: \[ \boxed{5.498} \]