(35sqrt(x ^ 2 + 10x + 25))/(x + 5) ,но x > - 5

To simplify the expression \(\frac{35\sqrt{x^2 + 10x + 25}}{x + 5}\) given that \(x > -5\), we start by simplifying the expression under the square root.

First, observe that:

\[ x^2 + 10x + 25 = (x + 5)^2 \]

Thus, we can rewrite the expression:

\[ \sqrt{x^2 + 10x + 25} = \sqrt{(x + 5)^2} \]

Since \(x > -5\), \(\sqrt{(x + 5)^2} = x + 5\).

Now replace \(\sqrt{x^2 + 10x + 25}\) in the original expression:

\[ \frac{35\sqrt{x^2 + 10x + 25}}{x + 5} = \frac{35(x + 5)}{x + 5} \]

Since \(x + 5\) is on both the numerator and the denominator (and not equal to zero when \(x > -5\)), we can simplify this to:

\[ 35 \]

So, the simplified expression is:

\[ \boxed{35} \] for \(x > -5\).