-9*(-1/3)³

To solve \(-9 \times \left(-\frac{1}{3}\right)^3\), we first calculate \(\left(-\frac{1}{3}\right)^3\).

\[ \left(-\frac{1}{3}\right)^3 = -\frac{1}{3} \times -\frac{1}{3} \times -\frac{1}{3} = -\frac{1}{27} \]

Now, substitute this back into the original expression:

\[ -9 \times -\frac{1}{27} \]

The negatives cancel each other out:

\[ 9 \times \frac{1}{27} = \frac{9}{27} = \frac{1}{3} \]

Thus, the final result is:

\[ \boxed{\frac{1}{3}} \]