-9*(-1/3)³

To solve \(-9 \times \left(-\frac{1}{3}\right)^3\), we first calculate \(\left(-\frac{1}{3}\right)^3\). \[ \left(-\frac{1}{3}\right)^3 = -\frac{1}{3} \times -\frac{1}{3} \times -\frac{1}{3} = -\frac{1}{27} \] Now, substitute this back into the original expression: \[ -9 \times -\frac{1}{27} \] The negatives cancel each other out: \[ 9 \times \frac{1}{27} = \frac{9}{27} = \frac{1}{3} \] Thus, the final result is: \[ \boxed{\frac{1}{3}} \]