Задача Задача №2615404
А
А
Let's break down the operations step by step to understand how the values of x and y change throughout the process.
Initialization:
- \( x := 1 \)
- \( y := 2 \times x \)
- Computation: \( y := 2 \times 1 = 2 \)
Update
y:- \( y := y \times x \)
- Computation: \( y := 2 \times 1 = 2 \)
Update
y:- \( y := y + 4 \)
- Computation: \( y := 2 + 4 = 6 \)
Update
y:- \( y := y \times x \)
- Computation: \( y := 6 \times 1 = 6 \)
Update
y:- \( y := y + 5 \)
- Computation: \( y := 6 + 5 = 11 \)
After performing all the operations, the final values are:
- \( x = 1 \)
- \( y = 11 \)
So, the final result is \( x = 1 \) and \( y = 11 \).