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To solve the equation \((0.1)^{2x-3} = 10\), follow these steps:

1. Express \(0.1\) as a power of 10: \((0.1) = 10^{-1}\).
2. Rewrite the equation: \((10^{-1})^{2x-3} = 10\).
3. Simplify using the property of exponents \((a^b)^c = a^{bc}\): \(10^{-2x+3} = 10^1\).
4. Since the bases are the same, set the exponents equal: \(-2x + 3 = 1\).
5. Solve for \(x\):
   • Subtract 3 from both sides: \(-2x = 1 - 3\).
   • \(-2x = -2\).
   • Divide by \(-2\): \(x = 1\).

So, the solution is \(x = 1\).