To solve the expression \( \frac{1}{2} + \frac{1}{6} - \frac{1}{3} \), we first need a common denominator.
The common denominator for 2, 6, and 3 is 6. Now, we can convert each fraction:
\[ \frac{1}{2} = \frac{3}{6} \] \[ \frac{1}{6} = \frac{1}{6} \] \[ \frac{1}{3} = \frac{2}{6} \]
Now substitute these back into the expression:
\[ \frac{3}{6} + \frac{1}{6} - \frac{2}{6} \]
Now we combine the fractions:
\[ \frac{3 + 1 - 2}{6} = \frac{2}{6} \]
This can be simplified:
\[ \frac{2}{6} = \frac{1}{3} \]
Thus, \( \frac{1}{2} + \frac{1}{6} - \frac{1}{3} = \frac{1}{3} \).