x3-216

To factor the expression \( x^3 - 216 \), we can recognize that it is a difference of cubes. The general formula for factoring a difference of cubes is:

\[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \]

In this case, we can identify:

• \( a = x \)
• \( b = \sqrt[3]{216} = 6 \)

Thus, we can rewrite the expression as:

\[ x^3 - 6^3 \]

Now, using the difference of cubes formula:

\[ x^3 - 6^3 = (x - 6)(x^2 + 6x + 36) \]

So, the factored form of \( x^3 - 216 \) is:

\[ (x - 6)(x^2 + 6x + 36) \]

If you have any further questions or need clarification, feel free to ask!