5х-10+11(-3+2х) =10

To solve the equation \( 5x - 10 + 11(-3 + 2x) = 10 \), let's first simplify it step by step. 1. Distribute \( 11 \) inside the parentheses: \[ 11(-3 + 2x) = 11 \cdot -3 + 11 \cdot 2x = -33 + 22x \] 2. Substitute this back into the equation: \[ 5x - 10 - 33 + 22x = 10 \] 3. Combine like terms on the left side: \[ (5x + 22x) + (-10 - 33) = 10 \] \[ 27x - 43 = 10 \] 4. Now, isolate \( x \) by adding \( 43 \) to both sides: \[ 27x = 10 + 43 \] \[ 27x = 53 \] 5. Finally, divide by \( 27 \) to solve for \( x \): \[ x = \frac{53}{27} \] So the solution to the equation \( 5x - 10 + 11(-3 + 2x) = 10 \) is: \[ x = \frac{53}{27} \]