5х-10+11(-3+2х) =10

To solve the equation \( 5x - 10 + 11(-3 + 2x) = 10 \), let's first simplify it step by step.

1. Distribute \( 11 \) inside the parentheses:

   \[ 11(-3 + 2x) = 11 \cdot -3 + 11 \cdot 2x = -33 + 22x \]

2. Substitute this back into the equation:

   \[ 5x - 10 - 33 + 22x = 10 \]

3. Combine like terms on the left side:

   \[ (5x + 22x) + (-10 - 33) = 10 \] \[ 27x - 43 = 10 \]

4. Now, isolate \( x \) by adding \( 43 \) to both sides:

   \[ 27x = 10 + 43 \] \[ 27x = 53 \]

5. Finally, divide by \( 27 \) to solve for \( x \):

   \[ x = \frac{53}{27} \]

So the solution to the equation \( 5x - 10 + 11(-3 + 2x) = 10 \) is:

\[ x = \frac{53}{27} \]