To solve the multiplication of the fractions, you multiply the numerators together and the denominators together. Here are the calculations for each expression:
\( \frac{2}{5} \times \frac{10}{3} \) \[ = \frac{2 \times 10}{5 \times 3} = \frac{20}{15} = \frac{4}{3} \]
\( \frac{12}{5} \times \frac{3}{4} \) \[ = \frac{12 \times 3}{5 \times 4} = \frac{36}{20} = \frac{9}{5} \]
\( \frac{18}{7} \times \frac{21}{4} \) \[ = \frac{18 \times 21}{7 \times 4} = \frac{378}{28} = \frac{189}{14} = \frac{27}{2} \]
\( \frac{9}{8} \times \frac{2}{3} \) \[ = \frac{9 \times 2}{8 \times 3} = \frac{18}{24} = \frac{3}{4} \]
\( \frac{15}{4} \times \frac{7}{3} \) \[ = \frac{15 \times 7}{4 \times 3} = \frac{105}{12} = \frac{35}{4} \]
\( \frac{17}{6} \times \frac{2}{9} \) \[ = \frac{17 \times 2}{6 \times 9} = \frac{34}{54} = \frac{17}{27} \]
\( \frac{14}{9} \times \frac{5}{3} \) \[ = \frac{14 \times 5}{9 \times 3} = \frac{70}{27} \]
\( \frac{2}{7} \times \frac{3}{4} \) \[ = \frac{2 \times 3}{7 \times 4} = \frac{6}{28} = \frac{3}{14} \]
\( \frac{16}{5} \times \frac{3}{8} \) \[ = \frac{16 \times 3}{5 \times 8} = \frac{48}{40} = \frac{6}{5} \]
Here are the final results for each multiplication:
- \( \frac{4}{3} \)
- \( \frac{9}{5} \)
- \( \frac{27}{2} \)
- \( \frac{3}{4} \)
- \( \frac{35}{4} \)
- \( \frac{17}{27} \)
- \( \frac{70}{27} \)
- \( \frac{3}{14} \)
- \( \frac{6}{5} \)