Реши

To solve the problem of determining the period, frequency, and amplitude from the graph, follow these steps: 1. **Amplitude (A)**: The amplitude is the maximum displacement from the equilibrium position (horizontal axis). You can see from the graph that the amplitude \( A \) is 3 meters. 2. **Period (T)**: The period is the time it takes for one complete cycle of the wave. From the graph, one full cycle spans from 0 to 4 seconds. Hence, the period \( T = 4 \) seconds. 3. **Frequency (f)**: Frequency is the reciprocal of the period, given by \( f = \frac{1}{T} \). So, \( f = \frac{1}{4} \) Hz or 0.25 Hz. Based on these observations, none of the options given exactly match the values calculated. However, the option with \( 2c; 0.5Гц; 1.5m \) is the closest in terms of period and an approximate frequency. There is an inconsistency between the amplitude value provided in any of the options with the correct \( 3m \) value from the graph. If you need the exact match, it might be worth reviewing the choices for other possible errors or misinterpretations.