2(2х-17)(2)-10(2х-17)+12=0

To solve the equation \( 2(2x - 17)(2) - 10(2x - 17) + 12 = 0 \), let's first simplify it:

1. Distribute the terms: \[ 2(2x - 17)(2) = 4(2x - 17) = 8x - 68 \] \[ -10(2x - 17) = -20x + 170 \]

2. Substitute these back into the equation: \[ 8x - 68 - 20x + 170 + 12 = 0 \]

3. Combine like terms: \[ (8x - 20x) + (-68 + 170 + 12) = 0 \] \[ -12x + 114 = 0 \]

4. Now isolate \( x \): \[ -12x = -114 \] \[ x = \frac{114}{12} = \frac{19}{2} = 9.5 \]

Therefore, the solution to the equation is: \[ \boxed{9.5} \]