6,1×(х-5,6)×(х-21)=0

To solve the equation \( 6.1 \times (x - 5.6) \times (x - 21) = 0 \), we can set each factor equal to zero. Since a product is equal to zero if at least one of its factors is zero, we can find the solutions by solving the following equations:

1. \( 6.1 = 0 \) (this does not provide a solution, as 6.1 is not zero)
2. \( x - 5.6 = 0 \)
3. \( x - 21 = 0 \)

Now, let's solve the second and third equations:

1. From \( x - 5.6 = 0 \): \[ x = 5.6 \]

2. From \( x - 21 = 0 \): \[ x = 21 \]

Thus, the solutions to the equation \( 6.1 \times (x - 5.6) \times (x - 21) = 0 \) are: \[ x = 5.6 \quad \text{and} \quad x = 21 \]