x-y=3 x-y=28

The system of equations you provided is:

1. \( x - y = 3 \)
2. \( x - y = 28 \)

If you look at both equations, you can see that the left-hand sides are identical (both are \( x - y \)). However, the right-hand sides are different (3 and 28). This indicates that there is no solution to this system of equations because a single expression (like \( x - y \)) cannot equal two different values simultaneously.

In conclusion, the system of equations is inconsistent, and there is no solution.