a + a + a = 30 b + b + a = 20 c + c + b = 13 a + b × c = ?

To solve for \( a + b \times c \) given the equations:

1. \( a + a + a = 30 \)
2. \( b + b + a = 20 \)
3. \( c + c + b = 13 \)

Let's solve each equation step by step.

From equation 1:

\[ 3a = 30 \implies a = \frac{30}{3} = 10 \]

Now, substituting \( a = 10 \) into equation 2:

\[ b + b + 10 = 20 \] \[ 2b + 10 = 20 \implies 2b = 20 - 10 \implies 2b = 10 \implies b = \frac{10}{2} = 5 \]

Next, substitute \( b = 5 \) into equation 3:

\[ c + c + 5 = 13 \] \[ 2c + 5 = 13 \implies 2c = 13 - 5 \implies 2c = 8 \implies c = \frac{8}{2} = 4 \]

Now we have the values:

• \( a = 10 \)
• \( b = 5 \)
• \( c = 4 \)

Now we can calculate \( a + b \times c \):

\[ b \times c = 5 \times 4 = 20 \] \[ a + b \times c = 10 + 20 = 30 \]

Thus, the answer is:

\[ \boxed{30} \]