(1 - 1/2)(1 - 1/3)(1 - 1/4)........ (1 - 1/2023) =

To simplify the expression

\[ (1 - \frac{1}{2})(1 - \frac{1}{3})(1 - \frac{1}{4}) \cdots (1 - \frac{1}{2023}), \]

we will first simplify each individual term:

\[ 1 - \frac{1}{n} = \frac{n-1}{n}. \]

So the product becomes:

\[ \frac{1}{2} \cdot \frac{2}{3} \cdot \frac{3}{4} \cdots \frac{2022}{2023}. \]

Now let's write this out as a single fraction:

\[ \frac{1}{2} \cdot \frac{2}{3} \cdot \frac{3}{4} \cdots \frac{2022}{2023} = \frac{1 \cdot 2 \cdot 3 \cdots \cdot 2022}{2 \cdot 3 \cdot 4 \cdots \cdot 2023}. \]

Notice that the numerator \( 1 \cdot 2 \cdot 3 \cdots \cdot 2022 \) is \( 2022! \), and the denominator is:

\[ 2 \cdot 3 \cdot 4 \cdots \cdot 2023 = \frac{2023!}{1}, \]

because \( 2023! = 1 \cdot 2 \cdot 3 \cdots \cdot 2023 \).

Thus, we can rewrite the entire product as:

\[ \frac{2022!}{2023!} = \frac{2022!}{2023 \cdot 2022!} = \frac{1}{2023}. \]

Finally, the value of the original product

\[ (1 - \frac{1}{2})(1 - \frac{1}{3})(1 - \frac{1}{4}) \cdots (1 - \frac{1}{2023}) \]

is

\[ \frac{1}{2023}. \]

Hence, the final result is

\[ \boxed{\frac{1}{2023}}. \]