DEF=32°.

In the given triangle \( \triangle DEF \), angle \( \angle DEF = 32^\circ \). Since it is a right triangle (as indicated by the square at angle \( \angle DFE \)), the right angle \( \angle DFE = 90^\circ \). To find \( \angle ECF \), we recognize that \( \angle DEF + \angle EFD + \angle EDF = 180^\circ \) for the triangle \( \triangle DEF \). Since \( \angle DFE = 90^\circ \), then: \[ \angle EDF = 90^\circ - \angle DEF = 90^\circ - 32^\circ = 58^\circ. \] Therefore, \( \angle ECF = \angle EDF = 58^\circ \).